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After market heater blower motor wiring

Discussion in 'Intermediate CJ-5/6/7/8' started by TrentCJ5, Jun 10, 2011.

  1. Jun 10, 2011
    TrentCJ5

    TrentCJ5 New Member

    Western Washington
    Joined:
    Jul 12, 2010
    Messages:
    16
    Hey folks, I bought a new heater box blower motor. The old blower had 3 wires, Red, Orange & Black. The new one only has two Orange and Black and they are interchangeable to reverse the fan.

    Any cleaver ways to make this a dual-speed blower, or is there a more appropriate replacement that has the 3 wires for dual-speed?
     
  2. Jun 11, 2011
    pete72

    pete72 Retro Aficionado

    Cumming, Georgia
    Joined:
    Feb 27, 2011
    Messages:
    158
    Try grounding the blower frame if you haven't done that already. The two wires may be for low speed and high speed.
     
  3. Jun 12, 2011
    TrentCJ5

    TrentCJ5 New Member

    Western Washington
    Joined:
    Jul 12, 2010
    Messages:
    16
    Unfortunately, tried that. The body isn't a ground...
     
  4. Jun 12, 2011
    BC3Jeep

    BC3Jeep Electric Bill

    NW Illinois
    Joined:
    Oct 8, 2009
    Messages:
    47
    Measure the amount of current that the blower draws and find a very low resistance high wattage resistor to match. Put this resistor in series with the mtor when you want it to run at lower speed. IF you could find a rheostat that could handle the wattage/current.... you could have an multi-speed motor.

    For specifics on HOW to do this, read a primer on Ohm's law......
     
  5. Jun 16, 2011
    TrentCJ5

    TrentCJ5 New Member

    Western Washington
    Joined:
    Jul 12, 2010
    Messages:
    16
    Not being an EE expert, this is what I think is right. Can you verify that my calculations are right?

    The old fan draws 1.7amps on low and 2.2 amps on high. The new fan draws 1.6amps. From my rudimentary Internet readings on OHM’slaw, to achieve the 36% drop in speed I think I need a 2.5 ohm 6w resistor.
     
  6. Jun 16, 2011
    Walt Couch

    Walt Couch sidehill Cordele, Ga. 2024 Sponsor 2023 Sponsor 2022 Sponsor

    cordele, Ga.
    Joined:
    Mar 29, 2007
    Messages:
    5,925
    when current (I) & voltage (E) are known you divide I into E to get Resistance.
    When current (I) & voltage (E) are known you multiply E times I to get Power (Watts).

    This is the law for DC circuits.
     
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